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2x^2+24=16
We move all terms to the left:
2x^2+24-(16)=0
We add all the numbers together, and all the variables
2x^2+8=0
a = 2; b = 0; c = +8;
Δ = b2-4ac
Δ = 02-4·2·8
Δ = -64
Delta is less than zero, so there is no solution for the equation
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